b^2=5b+12

Solution for b^2=5b+12 equation:

b^2=5b+12

We move all terms to the left:

b^2-(5b+12)=0

We get rid of parentheses

b^2-5b-12=0

a = 1; b = -5; c = -12;
Δ = b2-4ac
Δ = -52-4·1·(-12)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{73}}{2*1}=\frac{5-\sqrt{73}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{73}}{2*1}=\frac{5+\sqrt{73}}{2}
$